// you’re reading...
1 Star2 Stars3 Stars4 Stars5 Stars (10 votes, average: 5.00 out of 5)

Project Euler Solutions

Project Euler 102 Solution

Project Euler 102 Solution

Project Euler 102: Determine if the origin is contained inside a triangle.

Project Euler 102 Problem Description

Project Euler 102: Three distinct points are plotted at random on a Cartesian plane, for which -1000 ≤ x, y ≤ 1000, such that a triangle is formed.

Consider the following two triangles:

A(-340,495), B(-153,-910), C(835,-947)
X(-175,41), Y(-421,-714), Z(574,-645)

It can be verified that triangle ABC contains the origin, whereas triangle XYZ does not.

Using triangles.txt (right click and ‘Save Link/Target As…’), a 27K text file containing the co-ordinates of one thousand "random" triangles, find the number of triangles for which the interior contains the origin.

NOTE: The first two examples in the file represent the triangles in the example given above.


Project Euler 102 SolutionThere are a few ways to solve this problem. With having the point to check be the origin (0,0), then the easiest way is to check that the signs of the cross products are all positive or negative. This solution could be easily modified to check points other than the origin.

Project Euler 102
This program and method
solves all test cases for
Project Euler 102 on HackerRank

Project Euler 102 Solution

Runs < 0.001 seconds in Python 2.7.
download arrowUse this link to get the Project Euler 102 Solution Python 2.7 source.


    No afterthoughts yet.
Project Euler 102 Solution last updated


No comments yet.

Post a comment