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Project Euler Solutions

Project Euler 16 Solution

Project Euler 16 Solution

Project Euler 16: Sum of the digits in the number 2^1000

Problem Description

215 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26.

What is the sum of the digits of the number 21000?


Python supports arbitrary precision integers so calculating any obscenely large number can be done without external libraries.

Calculate 21000, split the digits and add them together. The str() function is used as an iterator and serves each character in 21000 until it reaches the end of the string.

I’m sure when this problem was created it was intended to be solved without large integer support or string manipulations, but such is the way of modern languages.

Project Euler 16 Solution

Runs < 0.001 seconds in Python 2.7.
download arrowUse this link to get the Project Euler 16 Solution Python 2.7 source.


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def sum_of_digits(n):
    r = 0
    n = int(abs(n))
    while n:
        r, n = r + n % 10, n / 10
    return r
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